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JEE MAIN - Chemistry (2018 (Offline) - No. 4)

Glucose on prolonged heating with HI gives
6-iodohexanal
n-Hexane
1-Hexene
Hexanoic acid

स्पष्टीकरण

As HI is a strong reducing agent, it reduces all the aldehydes and ketones to acohol and alcohols are further reduce to alkanes.

JEE Main 2018 (Offline) Chemistry - Biomolecules Question 152 English Explanation

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